CBSE Class 10 Maths Solutions provide students with detailed, step-by-step explanations for all topics. These solutions help clarify complex concepts and improve problem-solving skills. By practicing regularly, students can enhance their understanding and perform well in exams. Expert-backed, these solutions are key to mastering Class 10 Maths efficiently.
CBSE Class 10 Maths Solutions: Questions and Answers
What is the value of x if 2x + 5 = 15?
Answer: To solve for x, subtract 5 from both sides to get 2x = 10. Then, divide by 2 to get x = 5.
If a triangle has angles of 30°, 60°, and 90°, what type of triangle is it?
Answer: This is a right-angled triangle because one angle measures 90°.
Find the area of a circle with a radius of 7 cm.
Answer: The area of a circle is calculated using the formula πr². So, the area = π * 7² = 49π cm².
What is the perimeter of a rectangle with length 12 cm and width 5 cm?
Answer: The perimeter of a rectangle is calculated by adding twice the length and twice the width: 2(12 + 5) = 34 cm.
What is the solution to the equation 3y – 4 = 14?
Answer: Add 4 to both sides to get 3y = 18. Then divide by 3 to find y = 6.
A person invests ₹5000 at an interest rate of 5% per annum. What is the amount after 2 years?
Answer: Use the formula for simple interest: A = P(1 + rt). A = 5000(1 + 0.05 * 2) = ₹5500.
What is the volume of a cube with side length 4 cm?
Answer: The volume of a cube is side³, so the volume = 4³ = 64 cm³.
Simplify the expression: 2x + 3x – 5.
Answer: Combine like terms to get 5x – 5.
If the sides of a square are 8 cm, what is the area?
Answer: The area of a square is side². So, the area = 8² = 64 cm².
How many sides does a regular hexagon have?
Answer: A regular hexagon has 6 sides.
What is the product of 3 and 7?
Answer: The product is 21.
If the base of a triangle is 10 cm and its height is 5 cm, what is the area?
Answer: The area of a triangle is calculated by the formula (1/2) * base * height. So, the area = (1/2) * 10 * 5 = 25 cm².
Solve for x: 4x – 7 = 13.
Answer: Add 7 to both sides to get 4x = 20. Then divide by 4 to get x = 5.
What is the hypotenuse of a right triangle with legs of lengths 3 cm and 4 cm?
Answer: Use the Pythagorean theorem: a² + b² = c². So, 3² + 4² = c², which gives c² = 9 + 16 = 25, so c = 5 cm.
If a car travels 60 km in 2 hours, what is its average speed?
Answer: The average speed is distance/time. So, the average speed = 60/2 = 30 km/h.
Find the surface area of a cube with side length 5 cm.
Answer: The surface area of a cube is 6 * side². So, the surface area = 6 * 5² = 150 cm².
How many degrees are in a straight line?
Answer: A straight line measures 180°.
What is the LCM of 12 and 18?
Answer: The LCM of 12 and 18 is 36.
What is the sum of the interior angles of a quadrilateral?
Answer: The sum of the interior angles of a quadrilateral is 360°.
What is the square root of 49?
Answer: The square root of 49 is 7.
Additional Questions for CBSE Class 10 Maths
Simplify: 5(x + 3) – 2x.
Answer: Distribute 5 to get 5x + 15 – 2x. Simplify to get 3x + 15.
What is the perimeter of a square with a side of 6 cm?
Answer: The perimeter of a square is 4 * side. So, the perimeter = 4 * 6 = 24 cm.
If the diameter of a circle is 14 cm, what is its circumference?
Answer: The circumference of a circle is πd. So, the circumference = π * 14 = 44 cm (approx).
A cylindrical container has a radius of 3 cm and a height of 10 cm. What is its volume?
Answer: The volume of a cylinder is πr²h. So, the volume = π * 3² * 10 = 90π cm³.
What is the median of the numbers 5, 8, 12, 15, 20?
Answer: Arrange the numbers in order: 5, 8, 12, 15, 20. The median is the middle number, so the median = 12.
If a right triangle has one leg of 8 cm and the other leg of 15 cm, what is the length of the hypotenuse?
Answer: Use the Pythagorean theorem: a² + b² = c². So, 8² + 15² = c², which gives c² = 64 + 225 = 289, so c = 17 cm.
Solve for x: 5x – 10 = 20.
Answer: Add 10 to both sides to get 5x = 30. Then divide by 5 to get x = 6.
A triangle has sides of 7 cm, 24 cm, and 25 cm. Is it a right-angled triangle?
Answer: Check if 7² + 24² = 25². 49 + 576 = 625, which is true, so it is a right-angled triangle.
If the area of a circle is 154 cm², what is its radius?
Answer: The area of a circle is πr². So, 154 = π * r². Solving for r, we get r ≈ 7 cm.
What is the value of 2³?
Answer: 2³ = 8.
How many edges does a cube have?
Answer: A cube has 12 edges.
What is the sum of the first five prime numbers?
Answer: The first five prime numbers are 2, 3, 5, 7, and 11. Their sum is 28.
Find the value of y if 3y – 7 = 16.
Answer: Add 7 to both sides to get 3y = 23. Then divide by 3 to get y = 23/3.
A rectangle has a length of 20 cm and a width of 10 cm. What is its area?
Answer: The area of a rectangle is length * width. So, the area = 20 * 10 = 200 cm².
If a number is multiplied by 7 and then 5 is subtracted from the result, it equals 30. What is the number?
Answer: Let the number be x. Then, 7x – 5 = 30. Solving for x, we get x = 5.
Find the square root of 81.
Answer: The square root of 81 is 9.
What is the sum of the first 10 natural numbers?
Answer: The sum of the first 10 natural numbers is 55.
If the perimeter of a triangle is 24 cm and the lengths of two sides are 7 cm and 10 cm, what is the length of the third side?
Answer: The perimeter of a triangle is the sum of its sides. So, 7 + 10 + third side = 24. The third side = 24 – 17 = 7 cm.
Solve for x: 4x + 3 = 23.
Answer: Subtract 3 from both sides to get 4x = 20. Then divide by 4 to get x = 5.
A circle has a radius of 6 cm. What is its area?
Answer: The area of a circle is πr². So, the area = π * 6² = 36π cm².
Top Indian Books for CBSE Class 10 Maths Solutions: Expert-Backed Recommendations
R.D. Sharma - Mathematics for Class 10
R.S. Aggarwal - Mathematics for Class 10
ML Aggarwal - Mathematics for Class 10
H.C. Verma - Concept of Physics (Mathematics Section)
S.K. Gupta & Anubhuti Gangal - Mathematics for Class 10
Laxmi Publications - Mathematics Class 10
Target Publications - Mathematics Class 10
K.K. Verma - Maths Class 10
Xam Idea - Mathematics for Class 10
Mathematics for Class 10 by R. S. Agarwal & V. Aggarwal
Dinesh Maths Class 10
Pradeep’s New Course - Mathematics Class 10
Mathematics for Class 10 by R.D. Sharma (Multicolour Edition)
S. Chand’s Mathematics for Class 10
Oswal Publishers - Mathematics Class 10
RD Sharma - Mathematics for Class 10 (Old Edition)
All In One - Mathematics for Class 10
Cengage Learning - Mathematics for Class 10
Arihant’s Mathematics Class 10
Evergreen - Mathematics for Class 10
Mathematics is a crucial subject in the CBSE Class 10 curriculum, often causing both excitement and anxiety among students. Whether it's algebra, geometry, trigonometry, or statistics, mastering these topics is essential for scoring well in the exams. Having access to reliable CBSE Class 10 Maths solutions can make a world of difference when it comes to understanding complex concepts and practicing effectively.
Why CBSE Class 10 Maths Solutions Matter
Maths solutions play a vital role in helping students grasp the concepts in a structured way. With numerous chapters and formulas to remember, it’s easy to lose track of the basics. Well-organized solutions not only help students solve problems efficiently but also clarify any doubts they may have while studying. The key to success in CBSE Class 10 Maths is practice, and solutions provide a step-by-step approach to help students tackle every question with confidence.
CBSE Class 10 Maths solutions are designed to offer clear, concise, and easy-to-follow explanations. Each problem is broken down into smaller, manageable steps, which help students understand the process behind the solution. Instead of simply giving the final answer, the solutions guide students through each stage of the problem, reinforcing the importance of logical thinking and accuracy.
For instance, when working on algebraic expressions or quadratic equations, students are shown how to manipulate terms or apply the right formula. This ensures that they not only know the answer but also understand the reasoning behind it.
The CBSE Class 10 Maths syllabus is vast, covering a range of topics from Number Systems to Coordinate Geometry. Each topic comes with its own set of challenges, but with proper guidance, even the toughest chapters can be mastered. Solutions provided for each chapter give students the opportunity to practice problems of varying difficulty levels. These solutions ensure that no topic is left unexplored, making students well-prepared for the exams.
Using CBSE Class 10 Maths solutions is an excellent way to boost exam preparation. By solving sample problems and referring to solutions, students get an idea of the types of questions that are likely to appear in the exam. Regular practice, combined with referring to accurate and well-explained solutions, enhances problem-solving speed, ensuring that students can manage their time efficiently during the exam.
Additionally, by revisiting difficult questions and comparing solutions, students can identify recurring mistakes and rectify them before the actual exam. This approach promotes thorough revision and helps reduce the chances of errors.
Understand the Concept First: Before diving into the solutions, ensure that you have a clear understanding of the underlying concepts. Solutions work best when you already know the fundamentals.
Solve Problems Independently: Try solving problems on your own first. Use the solutions only when you're stuck, and analyze each step carefully.
Practice Regularly: Consistency is key in mastering Maths. Solve as many problems as you can, covering a variety of question types from the solutions.
Focus on Weak Areas: Pay extra attention to the topics or types of problems that challenge you the most. Use the solutions to practice and improve these areas.
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