Class 10 Maths Chapter 3 Exercise 3.2 solutions with step-by-step explanations and answers. Perfect for students to understand concepts and improve problem-solving skills.
Here are 50 sample questions and answers for Class 10 Maths Chapter 3 Exercise 3.2:
Sample Questions and Answers:
What is the solution to the equation 3x+4=103x + 4 = 103x+4=10? Answer: The solution is x=2x = 2x=2. Subtract 4 from both sides and divide by 3.
Solve for yyy: 2y−5=112y - 5 = 112y−5=11. Answer: Add 5 to both sides, then divide by 2. The solution is y=8y = 8y=8.
If 5x+3=235x + 3 = 235x+3=23, what is the value of xxx? Answer: Subtract 3 from both sides and then divide by 5. x=4x = 4x=4.
Simplify the expression 6a−3b+2a−5b6a - 3b + 2a - 5b6a−3b+2a−5b. Answer: Combine like terms. The simplified expression is 8a−8b8a - 8b8a−8b.
Find the value of xxx in the equation 4x−7=214x - 7 = 214x−7=21. Answer: Add 7 to both sides and then divide by 4. The solution is x=7x = 7x=7.
Solve the equation 7z+5=267z + 5 = 267z+5=26. Answer: Subtract 5 from both sides, then divide by 7. The value of z=3z = 3z=3.
If 2a+3b=102a + 3b = 102a+3b=10 and a=2a = 2a=2, what is the value of bbb? Answer: Substitute a=2a = 2a=2 into the equation and solve for bbb. The value of b=2b = 2b=2.
Solve 3x−5=163x - 5 = 163x−5=16. Answer: Add 5 to both sides, then divide by 3. The solution is x=7x = 7x=7.
What is the value of xxx in the equation 9x−4=329x - 4 = 329x−4=32? Answer: Add 4 to both sides, then divide by 9. The solution is x=4x = 4x=4.
Solve for yyy in the equation 6y+7=196y + 7 = 196y+7=19. Answer: Subtract 7 from both sides, then divide by 6. The value of y=2y = 2y=2.
Solve the equation 10x+4=3410x + 4 = 3410x+4=34. Answer: Subtract 4 from both sides and divide by 10. The solution is x=3x = 3x=3.
Simplify 8x+3y−4x−2y8x + 3y - 4x - 2y8x+3y−4x−2y. Answer: Combine like terms. The simplified expression is 4x+y4x + y4x+y.
What is the solution to 2x−4=82x - 4 = 82x−4=8? Answer: Add 4 to both sides and divide by 2. The solution is x=6x = 6x=6.
Find the value of xxx in the equation 5x−6=95x - 6 = 95x−6=9. Answer: Add 6 to both sides, then divide by 5. The solution is x=3x = 3x=3.
Solve for yyy: 3y+7=223y + 7 = 223y+7=22. Answer: Subtract 7 from both sides and divide by 3. The solution is y=5y = 5y=5.
What is the solution for xxx in 12x−4=3212x - 4 = 3212x−4=32? Answer: Add 4 to both sides and then divide by 12. The value of x=3x = 3x=3.
Solve the equation 3x+5=2x+103x + 5 = 2x + 103x+5=2x+10. Answer: Subtract 2x2x2x from both sides and then subtract 5 from both sides. The solution is x=5x = 5x=5.
Simplify the expression 7a−2b+4a+3b7a - 2b + 4a + 3b7a−2b+4a+3b. Answer: Combine like terms. The simplified expression is 11a+b11a + b11a+b.
If 5x+8=285x + 8 = 285x+8=28, what is the value of xxx? Answer: Subtract 8 from both sides and divide by 5. The value of x=4x = 4x=4.
Solve 4x+6=184x + 6 = 184x+6=18. Answer: Subtract 6 from both sides and divide by 4. The solution is x=3x = 3x=3.
What is the value of yyy in the equation 3y+4=163y + 4 = 163y+4=16? Answer: Subtract 4 from both sides, then divide by 3. The solution is y=4y = 4y=4.
Solve 8x−2=308x - 2 = 308x−2=30. Answer: Add 2 to both sides, then divide by 8. The value of x=4x = 4x=4.
If 3a+5=203a + 5 = 203a+5=20, what is the value of aaa? Answer: Subtract 5 from both sides and divide by 3. The value of a=5a = 5a=5.
Solve the equation 2x+7=152x + 7 = 152x+7=15. Answer: Subtract 7 from both sides, then divide by 2. The solution is x=4x = 4x=4.
Simplify the expression 5y−3x+2y−6x5y - 3x + 2y - 6x5y−3x+2y−6x. Answer: Combine like terms. The simplified expression is 7y−9x7y - 9x7y−9x.
What is the value of xxx in the equation 6x−8=286x - 8 = 286x−8=28? Answer: Add 8 to both sides, then divide by 6. The solution is x=6x = 6x=6.
Solve for xxx: 9x+12=579x + 12 = 579x+12=57. Answer: Subtract 12 from both sides, then divide by 9. The solution is x=5x = 5x=5.
If 5y−3=175y - 3 = 175y−3=17, what is the value of yyy? Answer: Add 3 to both sides, then divide by 5. The value of y=4y = 4y=4.
Solve 7x+6=307x + 6 = 307x+6=30. Answer: Subtract 6 from both sides, then divide by 7. The value of x=3.43x = 3.43x=3.43.
Find the solution for xxx in the equation 4x+10=264x + 10 = 264x+10=26. Answer: Subtract 10 from both sides, then divide by 4. The solution is x=4x = 4x=4.
Solve the equation 2x+5=112x + 5 = 112x+5=11. Answer: Subtract 5 from both sides and divide by 2. The value of x=3x = 3x=3.
Simplify the expression 5x+2y−3x+4y5x + 2y - 3x + 4y5x+2y−3x+4y. Answer: Combine like terms. The simplified expression is 2x+6y2x + 6y2x+6y.
Solve for yyy: 3y−4=173y - 4 = 173y−4=17. Answer: Add 4 to both sides, then divide by 3. The value of y=7y = 7y=7.
What is the solution to the equation 5x+8=385x + 8 = 385x+8=38? Answer: Subtract 8 from both sides and divide by 5. The solution is x=6x = 6x=6.
Solve for xxx: 6x+7=196x + 7 = 196x+7=19. Answer: Subtract 7 from both sides, then divide by 6. The value of x=2x = 2x=2.
Find the value of yyy if 2y+6=162y + 6 = 162y+6=16. Answer: Subtract 6 from both sides and divide by 2. The value of y=5y = 5y=5.
Solve the equation 7x−3=177x - 3 = 177x−3=17. Answer: Add 3 to both sides and divide by 7. The solution is x=2.86x = 2.86x=2.86.
If 4x+5=214x + 5 = 214x+5=21, what is the value of xxx? Answer: Subtract 5 from both sides and divide by 4. The solution is x=4x = 4x=4.
Simplify 3a+2b−5a+4b3a + 2b - 5a + 4b3a+2b−5a+4b. Answer: Combine like terms. The simplified expression is −2a+6b-2a + 6b−2a+6b.
What is the value of xxx in the equation 5x−3=175x - 3 = 175x−3=17? Answer: Add 3 to both sides, then divide by 5. The value of x=4x = 4x=4.
Solve for yyy: 2y+3=132y + 3 = 132y+3=13. Answer: Subtract 3 from both sides, then divide by 2. The value of y=5y = 5y=5.
Find the value of xxx in 7x−4=257x - 4 = 257x−4=25. Answer: Add 4 to both sides, then divide by 7. The value of x=4.14x = 4.14x=4.14.
Solve 4x+9=254x + 9 = 254x+9=25. Answer: Subtract 9 from both sides, then divide by 4. The solution is x=4x = 4x=4.
Simplify 3a+4b−2a+5b3a + 4b - 2a + 5b3a+4b−2a+5b. Answer: Combine like terms. The simplified expression is a+9ba + 9ba+9b.
What is the solution to 9x−5=329x - 5 = 329x−5=32? Answer: Add 5 to both sides, then divide by 9. The solution is x=4.11x = 4.11x=4.11.
Solve 6x−3=216x - 3 = 216x−3=21. Answer: Add 3 to both sides, then divide by 6. The value of x=4x = 4x=4.
Find the value of xxx if 3x+2=143x + 2 = 143x+2=14. Answer: Subtract 2 from both sides, then divide by 3. The solution is x=4x = 4x=4.
Solve for yyy: 5y−6=195y - 6 = 195y−6=19. Answer: Add 6 to both sides, then divide by 5. The value of y=5y = 5y=5.
What is the value of xxx in 7x−2=197x - 2 = 197x−2=19? Answer: Add 2 to both sides, then divide by 7. The solution is x=3x = 3x=3.
Solve the equation 4x+7=314x + 7 = 314x+7=31. Answer: Subtract 7 from both sides, then divide by 4. The value of x=6x = 6x=6.
These are the 50 sample questions and answers for Class 10 Maths Chapter 3 Exercise 3.2.
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Article: Class 10 Maths Chapter 3 Exercise 3.2 Solutions
Class 10 Maths is a pivotal stage for students aiming to build a solid foundation in mathematics. Chapter 3, Exercise 3.2 focuses on important concepts that play a significant role in preparing students for their board exams. Understanding these solutions in depth can greatly enhance students' problem-solving skills. In this article, we explore the key concepts of Exercise 3.2 and provide expert-backed recommendations on how to approach these solutions effectively.
The exercises in Chapter 3 are generally focused on algebra, equations, and their solutions. Exercise 3.2 deals with linear equations, a critical topic for understanding more complex concepts in algebra. Students are introduced to solving equations with one variable, a key skill needed for more advanced mathematics in higher classes.
Breaking Down the Solutions:
The first step in solving problems in Exercise 3.2 is to simplify the given equations. This involves moving terms from one side of the equation to another, using algebraic rules like addition, subtraction, multiplication, and division. A thorough understanding of how to manipulate equations is essential. Most questions involve solving for an unknown variable, and solutions require logical steps to isolate this variable.
One of the most effective methods for tackling these problems is by practicing the process of simplification. Students should begin by recognizing patterns in the equations and applying appropriate operations to isolate the variable. Using such methods, solving equations becomes much easier and more intuitive.
Types of Questions:
Exercise 3.2 contains a mix of direct and application-based questions. The direct questions focus on straightforward algebraic manipulations, while application-based questions require students to apply their knowledge in real-life contexts. For example, some questions may involve interpreting word problems, where students have to form equations based on the given information before solving them.
Another important aspect is word problems related to age, cost, time, and distance. These questions require students to create equations from real-world scenarios, which help in understanding the practical applications of algebraic equations. This approach makes it easier for students to relate abstract mathematical concepts to tangible, everyday situations.
Recommended Approach:
To excel in Exercise 3.2, it’s crucial for students to practice solving multiple types of problems. Revisiting the basics of solving linear equations can make a significant difference in grasping more complex problems. Practicing with sample papers, reference books, and previous year questions will also help students improve their problem-solving techniques.
For students aiming for a thorough understanding, referring to a variety of resources is key. Indian textbooks often come with detailed explanations and examples, which help students gradually build up their confidence and skill level. Step-by-step solutions are beneficial for understanding how to approach each problem systematically.
Moreover, while practicing problems from Exercise 3.2, it is important to focus on accuracy. Avoid skipping any intermediate steps, as understanding the process is more important than simply arriving at the answer. Developing a keen eye for small mistakes is crucial when solving complex equations.
Conclusion
Mastering the solutions of Class 10 Maths Chapter 3 Exercise 3.2 requires practice, patience, and the ability to break down problems into manageable parts. By focusing on understanding the methods behind solving linear equations, students can significantly improve their performance and prepare themselves for future mathematical challenges. With the right resources and practice techniques, achieving success in this chapter is entirely within reach.
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